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[note article incomplete] This article needs more work [/note] [QUICK DESCRIPTION] To control an integral $\int_E f(x)\ d\mu(x)$ or a sum $\sum_{n \in A} f(n)$, take its magnitude squared, expand it into a double integral $\int_E \int_E f(x) \overline{f(y)}\ d\mu(x) d\mu(y)$ or a double sum $\sum_{n \in A} \sum_{m \in A} f(n) \overline{f(m)}$, and then rearrange, for instance by making the change of variables $y=x+h$ or $n=m+h$. This often has the effect of replacing a phase $e^{2\pi i \phi(n)}$ or $e^{2\pi i \phi(x)}$ in the original integrand by a "differentiated" phase such as $e^{2\pi i (\phi(n+h)-\phi(n))}$ or $e^{2\pi i (\phi(x+h)-\phi(x))}$. Such differentiated phases are often more tractable to work with, especially if $\phi$ had a "polynomial" nature to it. [PREREQUISITES] harmonic analysis, analytic number theory [EXAMPLE] This is a classic example: to compute the integral $A := \int_{-\infty}^\infty e^{-\pi x^2}\ dx$, square it to obtain [math] A^2 = \int_{\R^2} e^{-\pi(x^2+y^2)}\ dx dy[/math] then rearrange using polar coordinates to obtain [math] A^2 = \int_0^2\pi \int_0^\infty e^{-\pi r^2} r\ dr d\theta.[/math] The right-hand side can easily be evaluated to be $1$, so the positive quantity $A := \int_{-\infty}^\infty e^{-\pi x^2}\ dx$ must also be $1$. [EXAMPLE] (Gauss sums) [EXAMPLE] (Weyl sums) [EXAMPLE] (The $TT^*$ method, say to obtain Hormander's $L^2$ oscillatory integral estimate) [EXAMPLE] (The large sieve) [GENERAL DISCUSSION] A variant of this trick is [[the van der Corput lemma for equidistribution]].
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